y=1/4(x-5)^2+4

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Solution for y=1/4(x-5)^2+4 equation:


x in (-oo:+oo)

y = (1/4)*(x-5)^2+4 // - (1/4)*(x-5)^2+4

y-((1/4)*(x-5)^2)-4 = 0

(-1/4)*(x-5)^2+y-4 = 0

y-1/4*(x-5)^2-4 = 0

y-1/4*(x-5)^2-4 = 0

5/2*x-1/4*x^2+y-25/4-4 = 0

5/2*x-1/4*x^2+y-41/4 = 0

5/2*x-1/4*x^2+y-41/4 = 0

5/2*x-1/4*x^2+y-41/4 = 0

DELTA = (5/2)^2-(-1/4*4*(y-41/4))

DELTA = y-4

y-4 = 0

y-4 = 0 // + 4

y = 4

DELTA = 0 <=> t_3 = 4

x = -5/2/(-1/4*2) i y = 4

x = 5 i y = 4

( x = ((y-4)^(1/2)-5/2)/(-1/4*2) or x = (-(y-4)^(1/2)-5/2)/(-1/4*2) ) i y > 4

( x = -2*((y-4)^(1/2)-5/2) or x = 2*((y-4)^(1/2)+5/2) ) i y > 4

y-4 > 0

y-4 > 0 // + 4

y > 4

x in { 5, -2*((y-4)^(1/2)-5/2), 2*((y-4)^(1/2)+5/2) }

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